(a-2⼀a^2+2a-a-1⼀a^2-4a+4)÷a-4⼀a+2,其中a=√2-1 (求过程)

2025-06-22 13:02:07
推荐回答(1个)
回答1:

(a-2/a^2+2a-a-1/a^2+4a+4)÷a-4/a+2
=[(a-2)/a(a+2)-(a-1)/(a+2)^2] ×(a+2)/(a-4)
=[(a-2)/a-(a-1)/(a+2)] ×1/(a-4)
=(a^2-4-a^2+a)/a(a+2) ×1/(a-4)
=(a-4)/a(a+2) ×1/(a-4)
=1/a(a+2)

=1/(√2-1)(√2+1)
=1/(2-1)
=1