x/(x-3)-2=m^2/(x-3)(x-2x+6)/(x-3)=m^2/(x-3)m^2x-3m^2=6x-18-x^2+3xx^2+(m^2-9)x-3m^2+18=0(x-3)(x+m^2-6)=0∵当x=3时,该分式方程有增根∴m^2-6=-3时,该分式方程有增根m^2-6=-3m^2=3m=±√3当m=±√3时,该分式方程有增根