1、由题意得:
X+Y+7=0
XY-5=0
则X+Y=-7 ,XY=5
3X²Y的3次方+3X的3次方Y²=3(XY)²(X+Y)=3(5)²(-7)=-525
2、由A²=B²+25得
A²-B²=25 即(A+B)(A-B)=25
因为A、B是正整数:则有:
A-B=1
A+B=25
所以A=13,B=12
|X+Y+7|+(XY-5)^2=0
那么
|X+Y+7|=0
(XY-5)^2=0
X+Y=-7
XY=5
3X^2Y^3+3X^3Y^2=3X^2Y^2*(X+Y)=3(XY)^2*(X+Y)=3*25*(-7)=-525