已知x+y=9,xy=20,求x^2+y^2-3xy的值

2025-06-23 09:14:53
推荐回答(4个)
回答1:

x^2+y^2-3xy
=(x+y)^2-5xy
=9^2-5*20
=81-100
=-19

回答2:

x^2+y^2+2xy-2xy-3xy
=(x+y)^2-5xy
=9^2-5*20
=81-100
=-19

回答3:

x^2+y^2-3xy=(x+y)的平方-5xy=81-100=-19

回答4:

x=4,y=5ory=4,x=5,这个没区别,^是什么意思,接下来代进去就好了