运用极限的夹逼性求解
因为1/(n^2+1^2)>1/(n^2+2^2)>...>1/(n^2+n^2)
所以n/(n^2+1^2)>1/(n^2+1^2)+1/(n^2+2^2)+...+1/(n^2+n^2)>n/(n^2+n^2)
因为lim(n->∞)n/(n^2+1^2)=lim(n->∞)n/(n^2+n^2)=0
所以根据极限的夹逼性，
lim(n->∞) [1/(n^2+1^2)+1/(n^2+2^2)+...+1/(n^2+n^2)]=0
lim(n->∞) (1+√2+√3+...+√n ) / (n√n)
=lim(n->∞)(1/n) ∑(i:1->n) √(i/n)
=lim(n->∞)(1/n) ∑(i: 1->n) √(i/n)
=∫(0->1) √x dx
= (2/3)[x^(3/2) ] (0->1)
=2/3
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