C语言,用for循环,求Fibonacci数列前40个数的程序如下:#include int main(void){ int a=1,b=1,t=0; printf("%d,",a); printf("%d,",b); for(int i=0;i<38;i++){ t=a+b; printf("%d,",t); a=b; b=t; } return 0;}
#include"stdio.h"
int main(void)
{
int i;
int a=1,b=1,n,t=0;
scanf("%d",&n);
if (n<=1)
{
printf("%d ",a);
}
else
{
printf("%d ",a);
printf("%d ",b);
for(i=0;i<(n-2);i++)
{
t=a+b;
printf("%d ",t);
a=b;
b=t;
}
}
return 0;
}