(1)容器质量忽略不计时,容器对桌面的压力:
F=G总=(1kg+5kg)×10N/kg=60N;
(2)容器底对桌面的压强:
p=
=F S
=6×103Pa;60N 100×10?4m2
(3)水对A点的压强:
p=ρgh=1.0×103kg/m3×10N/kg×(1m-0.35m)=6.5×103Pa;
(4)水对容器底的压强:
p′=ρgh′=1.0×103kg/m3×10N/kg×1m=1×104Pa.
答:(1)容器底对桌面的压力为60N;
(2)容器底对桌面的压强为6×103Pa;
(3)水对A点的压强为6.5×103Pa;
(4)水对容器底的压强为1×104Pa.