某人站在离地面高h=10m处的平台上,以水平速度v0=5m⼀s抛出一个质量m=1kg的小球,

2025-05-08 14:00:42
推荐回答(3个)
回答1:

1) 1/2 m V^2 = 12.5W
2) 1/2mV'^2 = 1/2mV^2 + mgh
=> v' = 根号(V^2+2gh) = 15 m/s

回答2:

1/2 m V^2 = 12.5W
2) 1/2mV'^2 = 1/2mV^2 + mgh
=> v' = 根号(V^2+2gh) = 15 m/s

回答3:

1题:W=1/2MV*V=12.5J
2题:15m/s