Python判断闰年与否

2025-05-07 23:45:01
推荐回答(1个)
回答1:

def leap(year):
    if year % 400 == 0:
        return True
    else:
        if year % 100 == 0:
            return False
        else:
            if year % 4 == 0:
                return True
            else:
                return False