设0<a<b<c<180度且sina+sinb+sinc=0,cosa+cosb+cosc=0,则b-a=?

xiele
2025-05-24 10:35:19
推荐回答(1个)
回答1:

(sinc)^2=(sinb+sina)^2
(cosc)^2=(cosb+cosa)^2
两式展开相加:
1=2+2(sinbsina+cosbcosa)
sinasinb+cosbcosa=-0.5
cos(b-a)=-0.5
b-a=120度