[3x/(x-2)-x/(x+2)]÷x/(x^2-4)=[3x(x+2)-x(x-2)]÷x=(3x^2+6x-x^2+2x)÷x=(2x^2+8x)÷x=2x+8取x=0的话原式=2x+8=8如果不懂，请追问，祝学习愉快！
